Comments on: a + (b x c) = 15,000,000 http://www.mailwatch.co.uk/2006/06/15/a-b-x-c-15000000/ Watching the Daily Mail Sat, 13 Mar 2010 23:38:14 +0000 http://wordpress.org/?v=2.8 hourly 1 By: GWO http://www.mailwatch.co.uk/2006/06/15/a-b-x-c-15000000/comment-page-1/#comment-120228 GWO Fri, 16 Jun 2006 13:59:22 +0000 http://www.bigdaddymerk.co.uk/mailwatchnew/?p=873#comment-120228 <i>y = Ae^(-x) + Be^(-2x) - xe^(-2x), which I reckon is correct.</i>Spot on. So y(0) = A + B = 0 y'(0) = -A - 2B - 1 = 1 Quick eliminations A = -B, and -B = 2, so I make y = 2 e^(-x) - 2 e^(-2x) - x e^(-2x) Still, I'd give that 8/10. :) y = Ae^(-x) + Be^(-2x) – xe^(-2x), which I reckon is correct.Spot on.

So y(0) = A + B = 0
y’(0) = -A – 2B – 1 = 1

Quick eliminations A = -B, and -B = 2, so I make

y = 2 e^(-x) – 2 e^(-2x) – x e^(-2x)

Still, I’d give that 8/10. :)

]]> By: Consignia http://www.mailwatch.co.uk/2006/06/15/a-b-x-c-15000000/comment-page-1/#comment-120218 Consignia Fri, 16 Jun 2006 12:54:12 +0000 http://www.bigdaddymerk.co.uk/mailwatchnew/?p=873#comment-120218 Sorry, I totally buggered up the bit at the end. I got as far as y = Ae^(-x) + Be^(-2x) - xe^(-2x), which I reckon is correct. Sorry, I totally buggered up the bit at the end. I got as far as y = Ae^(-x) + Be^(-2x) – xe^(-2x), which I reckon is correct.

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